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Proton Pass
Plan-Les-Ouates, Switzerland-based cybersecurity company founded 2014. Private. Operates in encrypted communications and digital privacy. Serves individuals and businesses with encrypted email, VPN, cloud storage, and password management.
Entry price
$2.99
Pass Plus · /mo, billed annually
Plans tracked
4
no add-ons
Pricing changes
0
None published yet
Pricing model
Subscription
Free tier available
Pricing Change History
0 changesNo tracked pricing changes yet — new verified changes land here automatically.
Research Proton Pass's pricing with the Pulse Agent
Ask anything about Proton Pass's plans, packaging shifts, and how it compares across the market — answered live from verified data.
Ask the agentCurrent plans
Captured| Plan | Price |
|---|---|
| Proton Free | Free |
| Pass Plus | $2.99 /mobilled annually · $4.99 billed monthly |
| |
| Pass Family | $4.99 /mobilled annually · $6.99 billed monthly |
| |
| Proton Unlimited | $9.99 /mobilled annually · $12.99 billed monthly |
| |
Company Facts
Free tierYes
Employees101-1000
Tracked sinceMar 20, 2026
Pricing last seenJun 20, 2026
Websiteproton.me
How Proton Pass compares with its peers
| Company | Entry price | Last change |
|---|---|---|
B Bitwarden | $1.65 /mo, billed annually | Jul 3, 2026 |
1 1password | $2.49 /user/mo, billed annually | Jul 6, 2026 |
L Lastpass | $3 /mo, billed annually | Sep 14, 2026 |
D Dashlane | $4 /user/mo, billed annually | Jul 27, 2026 |
K Keeper Security, Inc. | $2 /user/mo, billed annually | Jul 3, 2026 |
N NordPass | $1.99 /user/mo, billed annually | Aug 4, 2026 |
Proton Pass pricing FAQ
- How much does Proton Pass cost?
- Proton Pass pricing starts at $2.99/mo on Pass Plus, billed annually. Proton Pass lists 4 plans on its pricing page; the Proton Free plan is free.
- Does Proton Pass have a free plan?
- Yes. Proton Pass's Proton Free plan is free; paid plans start at $2.99/mo on Pass Plus, billed annually.
- What pricing model does Proton Pass use?
- Proton Pass uses subscription pricing across 4 plans, with a free tier.